A rifle bullet loses 1/20th of its velocity in passing through a plank. What will be the least number of such planks required to just stop the bullet? | A rifle bullet loses 1/20th of its velocity in passing through a plank. What will be the least number of such planks required to just stop the bullet is..
Let thikness is x
Initial
Velocity =V
Final
velocity =V{1-(1/20)}
=19v/20
=>(19v/20)2=v2-2ax[v2=u2-2as]
=>2as=V2[1-(19/20)2]
=>2as=V2[(39/400]-------(i)
For
n planks
02=v2-2anx
V2=2anx-------(ii)
From equation (i)/(ii)
Therefore,
n=400/39 ≈ 10.3
So, 11planks are required to stop the bullet.
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